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The verb gen below generates any permutation of order > 1 as a sequence of the two permutations 0&C. and _2&C. . It is based on the idea that p=: 0 C. i.n q=: _2 C. i.n can generate p0=: {/ (n=>:i.2+n) { p,:q q0=: q which are similar to p and q except that the leading. item is invariant under permutation by p0 and q0 . e.g. for n=: 7.
www.jsoftware.com/jwiki/Essays/Symmetric%20Array
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- GUYON. 15 LIPPI - ALEXIS BADEL - 6p1p6p0p8p2p0p7p8p5p.
www.lescourseshippiques.com/cache/pages/performances/1400/performances.html
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tabs.ultimate-guitar.com/s/shinedown/trade_yourself_in_ver3_tab.htm
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www.photos.com/clipart-vectors/dutch-flag
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Изобретение относится к радиотехнике, а точнее, к приборам обнаружения перемещения человека и различных предметов, и может быть использовано для охранной сигнализации в различных помещениях. Способ контроля положения подвижных объектов, например подвижных железнодорожных составов, и система для его осуществления (варианты) // 2115140.
www.FindPatent.ru/patent/80/801720.html
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1 The nine-element processing window Image ImageData Data (Impulse (Impulsenoise noisecorrupted) corrupted) (c) Output from night-points median filter Window Mask (3x3 pixels) Compute Pavgj t1 Pavg j ∈ noise ? no Yes (d) Output from fuzzy filter [9] Output = P0 yes Output = y Fig.
www.ee.nchu.edu.tw/Pic/Writings/2422_APCMTA2000.PDF
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The harvested solar energy will be converted into electrical energy and will increase the sensors batteries residual energy level sequentially. • ∀sj,t ∈ X j , Aj (wt , sj,t ) = {p0 , . . . , psj,t } is a finite set of available transmission powers for sensor j. This set satisfies Aj (wt, sj, t - 1) ⊂ Aj (wt, sj, t): more powers are available at higher states.
jwcn.eurasipjournals.com/content/pdf/1687-1499-2012-158.pdf
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gi ∈ K , since fi ∈ K and xs 1 . . . xd ∈ core(I ) ⊂ K . Now since the ai,j are general elements of k , and k is innite, we can choose α1 , . . . , αd ∈ k such that d i=1 αi ai,p = 0 for all p = 1, . . . , d with p = q , and such that d q −nq +kq αi gi = xs q d+1. i=1 αi ai,d+1 = 1. Then xj j j =q s +kj . i=1 Notice that this is a monomial in K , and is thus in core(I ) = mono(K ). Similarly, for any xed c, we can choose α1...
etd.nd.edu/ETD-db/theses/available/etd-04162010-172451/unrestricted/SmithB042010D.pdf
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the value of P+ while satisfying these bounds . Since β > 0 and P+ = e−2β P− , it follows that P+ ≤ P− . If we additionally assume that P+ ≤ P0 ≤ P−, then the rst six inequalities are redundant and one can simply study the last two (that is, the bottom row).
www.math.ubc.ca/~andrewr/pubs/ErgodicProof.pdf
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www.Higer-Bus.ru/parts
